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In an experiment for determination of re...

In an experiment for determination of refractive index of glass of a prism by `i-delta`, plot it was found thata ray incident at angle `35^circ`, suffers a deviation of `40^circ` and that it emerges at angle `79^circ`. In that case which of the following is closest to the maximum possible value of the refractive index?

A

1.5

B

1.6

C

1.7

D

1.8

Text Solution

Verified by Experts

The correct Answer is:
A

`delta=40^(@), I.=79^(@) i=35^(@)`
`delta=i+I.-A`
`rArr" "A=74^(@)`
Let us assume refractive index `mu`
`mu=(sin((A+delta)/(2)))/(sin((A)/(2)))=(sin((74^(@)+40^(@))/(2)))/(sin 37^(@))`
`mu=1.89`
The closest value is 1.5
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