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Dehydration of ethyl alcohol with conc. ...

Dehydration of ethyl alcohol with conc. `H_(2)SO_(4)` at 413 K gives......

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To solve the question regarding the dehydration of ethyl alcohol (ethanol) with concentrated sulfuric acid at 413 K, we will follow these steps: ### Step 1: Identify the Reactants The reactant in this reaction is ethyl alcohol (ethanol), which has the molecular formula \( \text{C}_2\text{H}_5\text{OH} \). ### Step 2: Understand the Reaction Conditions The reaction is carried out using concentrated sulfuric acid (\( \text{H}_2\text{SO}_4 \)) at a temperature of 413 K. Under these conditions, sulfuric acid acts as a dehydrating agent. ...
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Give the product of reaction of ethyl alcohol with conc. H_(2)SO_(4) at (a) 0^(@)C (b) room temperature (c) 130^(@)C (d) 180^(@)C .

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Knowledge Check

  • Dehydration of methyl alcohol with conc. H_(2)SO_(4) yields

    A
    methane
    B
    ethane
    C
    dimethyl ether
    D
    acetone

  • Dehydration of methyl alcohol with conc. H_2SO_4 , gives

    A
    methane
    B
    ethane
    C
    methyl hydrogen sulphate
    D
    dimethyl ether

  • The dehydration of 2- Methyl butanol with conc. H_(2)SO_(4) gives

    A
    `2-`Methyl pent`-2-`ene
    B
    Pentene
    C
    `2-`Methyl but`-2-`ene as major product
    D
    `2-`Methylbutene as major product

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    Dehydration of cyclopentyl carbinol with conc. H_(2)SO_(4) forms

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