Which one of the following compounds would not be easily oxidised by `K_(2)Cr_(2)O_(7)` and sulphuric acid ?

Options

A. `CH_(3)CH_(2)OH`
B. `(CH_(3))_(2)CHOH`
C. `(CH_(3))_(3)COH`
D. `CH_(3)CHO`.

Answer

To determine which compound would not be easily oxidized by \( K_2Cr_2O_7 \) and sulfuric acid, we need to analyze the oxidation behavior of different types of alcohols.

### Step-by-Step Solution:

1. **Understanding Oxidation of Alcohols**:
- Alcohols can be classified into three categories: primary, secondary, and tertiary.
- Primary alcohols can be oxidized to aldehydes, and further to carboxylic acids.
- Secondary alcohols can be oxidized to ketones.
- Tertiary alcohols generally do not oxidize easily because they lack a hydrogen atom on the carbon bearing the hydroxyl group.

2. **Identifying the Compounds**:
- We need to look at the structures of the given compounds.
- For example, if we have a primary alcohol (like ethanol), it can be oxidized to acetaldehyde and then to acetic acid.
- A secondary alcohol (like isopropanol) can be oxidized to acetone.
- A tertiary alcohol (like tert-butanol) has no hydrogen atom attached to the carbon with the hydroxyl group, making it resistant to oxidation.

3. **Analyzing the Compounds**:
- If we have a compound that is a tertiary alcohol, it will not have a replaceable hydrogen atom on the carbon that bears the hydroxyl group.
- This means that it cannot form a carbonyl group (C=O) upon oxidation, which is necessary for further oxidation to occur.

4. **Conclusion**:
- Among the given options, the compound that is a tertiary alcohol will not be easily oxidized by \( K_2Cr_2O_7 \) and sulfuric acid.
- Therefore, the answer is the tertiary alcohol, as it lacks the necessary hydrogen atom for oxidation.

### Final Answer:
The compound that would not be easily oxidized by \( K_2Cr_2O_7 \) and sulfuric acid is the tertiary alcohol.

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