The compound `A` on treatment with `Na` gives `B`, and with `PCl_(5)` gives `C`. `B` and `C` react together to give di Ethyl ether. `A,B` and `C` are in the order

Options

A. `C_(2)H_(5)OH,C_(2)H_(6),C_(2)H_(5)Cl`
B. `C_(2)H_(5)OH,C_(2)H_(5)Cl,C_(2)H_(5)ONa`
C. `C_(2)H_(5)Cl,C_(2)H_(6),C_(2)H_(5)OH`
D. `C_(2)H_(5)OH,C_(2)H_(5)ONa, C_(2)H_(5)Cl`

Answer

D

Explanation

`CH_(3)underset((A))(CH_(2))OHoverset(Na)toCH_(3)underset((B))(CH_(2))ONa`
`CH_(3)underset((A))(CH_(2))OHoverset(PCl_(5))toCH_(3)underset((C))(CH_(2))Cl`
`CH_(3)underset((B))(CH_(2))ONa+Clunderset((C))(CH_(2))CH_(3)tounderset("Diethylether")(CH_(3)CH_(3))OCH_(2)CH_(3)`