An oxygen containing organic compound was found to contain 52% carbon and 13% of hydrogen. Its vapour density is 23. The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is

Options

A. Ethanal
B. Ethanal
C. Methoxy methane
D. Methoxy ethane

Explanation

To solve the problem step by step, we will analyze the information provided and derive the required compound and its functional isomer.

### Step 1: Determine the percentage composition of the compound
The compound contains:
- 52% Carbon (C)
- 13% Hydrogen (H)
- The remaining percentage is Oxygen (O).

Calculating the percentage of Oxygen:
\[ \text{Percentage of Oxygen} = 100\% - (52\% + 13\%) = 35\% \]

### Step 2: Calculate the molecular mass using vapor density
The vapor density (VD) is given as 23. The molecular mass (M) can be calculated using the formula:
\[ M = 2 \times \text{VD} \]
Substituting the value:
\[ M = 2 \times 23 = 46 \, \text{g/mol} \]

### Step 3: Calculate the mass of each element in the compound
Using the molecular mass, we can find the mass of each element:
- Mass of Carbon:
\[ \text{Mass of C} = \frac{52}{100} \times 46 = 23.92 \, \text{g} \]
- Mass of Hydrogen:
\[ \text{Mass of H} = \frac{13}{100} \times 46 = 5.98 \, \text{g} \]
- Mass of Oxygen:
\[ \text{Mass of O} = \frac{35}{100} \times 46 = 16.1 \, \text{g} \]

### Step 4: Calculate the number of atoms of each element
Now, we find the number of atoms of each element:
- Number of Carbon atoms:
\[ \text{Number of C} = \frac{23.92}{12} \approx 1.99 \approx 2 \, \text{C atoms} \]
- Number of Hydrogen atoms:
\[ \text{Number of H} = \frac{5.98}{1} \approx 6 \, \text{H atoms} \]
- Number of Oxygen atoms:
\[ \text{Number of O} = \frac{16.1}{16} \approx 1.006 \approx 1 \, \text{O atom} \]

### Step 5: Write the empirical formula
From the calculations, we have:
- 2 Carbon atoms
- 6 Hydrogen atoms
- 1 Oxygen atom

Thus, the empirical formula of the compound is:
\[ \text{C}_2\text{H}_6\text{O} \]

### Step 6: Determine the compound
The molecular formula is also C2H6O, which corresponds to ethanol (C2H5OH) or dimethyl ether (CH3OCH3). Given that the compound reacts with sodium to liberate hydrogen, it is likely ethanol (an alcohol).

### Step 7: Identify the functional isomer
The functional isomer of ethanol (C2H6O) is dimethyl ether (CH3OCH3).

### Final Answer
The functional isomer of the compound is **Dimethyl Ether (CH3OCH3)**.

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