Carbolic acid is oxidised by acidified sodium dichromate to give

Options

A. Benzoquinone
B. Anthraquinone
C. Ethylmethyl ketone
D. Acetone

Explanation

To solve the question regarding the oxidation of carbolic acid (phenol) by acidified sodium dichromate, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Carbolic Acid**:
- Carbolic acid is another name for phenol, which has the chemical formula C6H5OH.

2. **Understand the Oxidizing Agent**:
- Sodium dichromate (Na2Cr2O7) in the presence of dilute sulfuric acid (H2SO4) is a strong oxidizing agent.

3. **Reaction of Phenol with Sodium Dichromate**:
- When phenol is treated with sodium dichromate, it undergoes oxidation. The reaction can be summarized as follows:
\[ \text{C}_6\text{H}_5\text{OH} + \text{Na}_2\text{Cr}_2\text{O}_7 \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_6\text{H}_4\text{O} + \text{Cr}^{3+} + \text{H}_2\text{O} \]
- The product formed from the oxidation of phenol is benzoquinone (C6H4O).

4. **Conclusion**:
- Therefore, when carbolic acid (phenol) is oxidized by acidified sodium dichromate, the product formed is **benzoquinone**.

### Final Answer:
Carbolic acid is oxidized by acidified sodium dichromate to give **benzoquinone**.

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