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in the reaction 2CH3 underset(O ) un...

in the reaction
` 2CH_3 underset(O ) underset(||) C CH_3 underset("Catalyst ") overset("Base") to A underset("Catalyst") overset("Acid ") to B `
the product B is

A

`CH_3 COH (CH_3 )CH_2 COCH_3`

B

`CH_3COH (CH_3 ) CH_2 COOH `

C

`CH_3 C (CH_3 ) =CH COCH_3`

D

`CH_3 CH=CHCH_2 COCH_3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given reaction step by step. ### Step 1: Identify the Reactants The reactants in the reaction are two molecules of 2-butanone (CH₃C(O)CH₃). This is a ketone with the structure: ``` O || CH₃-C-CH₃ ``` ### Step 2: Understand the Reaction Conditions The reaction is performed in the presence of a base catalyst initially. The base catalyst is typically a hydroxide ion (OH⁻), which suggests that we are likely performing an aldol condensation reaction. ### Step 3: Perform the Aldol Condensation When two molecules of 2-butanone react under basic conditions, they undergo an aldol condensation. The base deprotonates one of the alpha-hydrogens, leading to the formation of an enolate ion. This enolate ion then attacks the carbonyl carbon of another 2-butanone molecule. The reaction can be represented as follows: 1. Formation of the enolate ion: ``` CH₃C(O)CH₃ + OH⁻ → CH₃C(−)C(=O)CH₃ ``` 2. Nucleophilic attack: ``` CH₃C(−)C(=O)CH₃ + CH₃C(O)CH₃ → CH₃C(OH)(C=O)CH₂C(=O)CH₃ ``` ### Step 4: Dehydration to Form Product A The product formed after the aldol condensation is a β-hydroxy ketone. This intermediate can undergo dehydration (loss of water) to form an α,β-unsaturated ketone. ### Step 5: Acid-Catalyzed Reaction The next step involves the addition of an acid catalyst (H⁺). This step typically involves protonation of the carbonyl oxygen, making the carbonyl carbon more electrophilic, which can lead to further reactions or rearrangements. ### Step 6: Identify Product B After the acid-catalyzed step, the final product B is likely to be mesityl oxide, which has the structure: ``` O || CH₃-C-CH=C-CH₃ ``` Thus, the final product B is **mesityl oxide (4-methyl-3-penten-2-one)**. ### Final Answer The product B is **mesityl oxide (4-methyl-3-penten-2-one)**. ---

To solve the problem, we need to analyze the given reaction step by step. ### Step 1: Identify the Reactants The reactants in the reaction are two molecules of 2-butanone (CH₃C(O)CH₃). This is a ketone with the structure: ``` O || ...
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