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In E. coli DNA, AT//GC ratio is 0.93. If...

In E. coli DNA, `AT//GC` ratio is `0.93`. If the number of moles of adenine in its `DNA` sample is `465,000,` calculate the number of moles of guanine present.

Text Solution

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We know that the number of moles of adenine should be equal to those of thymine. Therefore,
`A+T=2xx465,000=930,000`
`"Now, "A+T//G+C=0.93`
`therefore" "G+C=(A+T)/(0.93)=(930,000)/(0.93)=1000,000`
Now moles of guanine should be equal to cytosine.
`G=(1000,000)/(2)=500,000.`
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