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Glucose, Mannose and fructose give ident...

Glucose, Mannose and fructose give identical osazones. Explain

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The osazone formation involves the reaction at `C_(1) and C_(2)` carbon while the rest of the molecule remains intact. Since glucose and fructose differ from each other only in the arrangement of atoms `C_(1) and C_(2)` therefore, they give the same osazone as shown:
`{:(" "CHO),(" |"),(" "CHOH),(" |"),(" "(CHOH)_(3)),(" |"),(" "CH_(2)OH),(" Glucose"):}underset(underset(-NH_(3),-2H_(2)O)(-C_(6)H_(5)NH_(2),))overset(3C_(6)H_(5)NHNH_(2))rarr{:(" "CH=N NHC_(6)H_(5)),(" |"),(" "C=N NHC_(6)H_(6)H_(5)),(" |"),(" "(CHOH)_(3)),(" |"),(" "CH_(2)OH),(" Glucosazone"):}`
`{:(" C"H_(2)OH),(" |"),(" C=O"),(" |"),(("CHOH")(3)),(" |"),(" C"H(2)OH),("Fructose"):}undersetunderset(-NH_(3),-2H_(2)O)(-C_(6)H_(5)NH_(2))overset(3C_(6)H_(5)NHNH_(2))rarr{:(" CH"=N NHC_(6)H_(5)),(" |"),(" C"=N NHC_(6)H_(5)),(" |"),((CHOH)(3)),(" |"),((CH(2)OH)),("Fructosazone"):}`
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Knowledge Check

  • A : Glucose, Mannose and Fructose form identical osazone. R : Glucose, Mannose and Fructose have identical configuration at 3rd, 4th and 5th carbon atom

    A
    If both Assertion and Reason are true and the reason is the correct explanation of the assertion, then mark (1).
    B
    If both Assertion and Reason are true but the reason is not the correct explanation of the assertion, then mark (2).
    C
    If Assertion is true statement but Reason is false, then mark (3).
    D
    If both Assertion and Reason are false statements, then mark (4).
  • Glucose and fructose from identical osazones because :

    A
    they are monosaccharide
    B
    they are reducing sugar
    C
    they are epimer
    D
    their configuration differ only at C-1 and C-2
  • Glucose and fructose are :

    A
    Diastereomers
    B
    Anomers
    C
    Epimers
    D
    Functional Isomers
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