Glucose shows mutarotation when it dissolves in water. The specific rotation of `alpha`-D glucose and `beta`-D- glucose is `+112.2^(@)` and `+18.7^(@)` respectively. Calculate the percentage of two anomers present at equilibrium mixture with a specific rotation of `+52.6^(@)`.

Explanation

To solve the problem of calculating the percentage of the two anomers (α-D-glucose and β-D-glucose) present in an equilibrium mixture with a specific rotation of +52.6°, we can follow these steps:

### Step 1: Understand the Given Data
- Specific rotation of α-D-glucose = +112.2°
- Specific rotation of β-D-glucose = +18.7°
- Specific rotation of the equilibrium mixture = +52.6°

### Step 2: Set Up the Equation
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