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In a polymer sample, 30% molecules have ...

In a polymer sample, `30%` molecules have molecular mass `20000, 40%` have molecular mass `30000` and the rest `30%` have `60000`. Calculate their number average and mass average molecular masses.

Text Solution

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The polymer contains `30%` molecules of molecular mass `20,000,40%` molecules of molecular mass 30,000 and rest `30%` of molecules of molecular mass `60,000`. Thus,
`bar(M)_(N)=(SigmaN_(i)M_(i))/(SigmaM_(i))`
`bar(M)_(N)=((30xx20000)+(40xx30000)+(30xx60000))/(30+40+30)=36000`
`bar(M)_(W)=(SigmaN_(i)M^(2))/(SigmaN_(i)M_(i))`
`bar(M)_(W)=(30(20000)^(2)+40(30000)^(2)+30(60000)^(2))/(30xx20000+40xx30000+30xx60000)=43333`

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