" 11."x^(3)-64x

Fractorise: x ^(3) - 64x

One root of the following given equation x^(5)-14x^(4)+31x^(3)-64x^(2)+19x+130=0

The HCF of 8x^(4) - 16x^(3) - 40x^(2) + 48x and 16x^(5) + 64x^(4) + 80x^(3) + 32x^(2) is

If the zeros of the polynomial 64x^(3)-144x^(2)+92x15 are in AP,then the difference between the largest and the smallest zeroes of the polynomial is

If alpha,beta and gamma are the three zeroes of the polynomial p(x)=x^(3)64x-14, what is the value of alpha^(3)+beta^(3)+gamma^(3)?

If f(x) = {:((x^(4)-64x)/(sqrt(x^(2)+9)-5),",",x != 4),(k,",",x =4):} is continous at x = 4, then k =

If f(x) = {:((x^(4)-64x)/(sqrt(x^(2)+9)-5),",",x != 4),(k,",",x =4):} is continous at x = 4 , then k =

A : the equation whose roots are multiplied by 2 of those of x^(5) - 2x^(4) + 3x^(3) - 2x^(2) + 4x + 3 =0 is x^(5) - 4x^(4) + 12x^(3) - 16x^(2) + 64x + 96 = 0 . R: the equation whose roots are multiplied by k of those of f(x) = 0 is f(x/k) = 0.

If alpha and beta be two roots of the equation x^(2) -64x+ 256=0 . Then the value of ((alpha^(3))/(beta^(5)))^(1/8) + ((beta^(3))/(alpha^(5)))^(1/8) is :

lim_(x rarr0)((4+x)^(3)-64)/(x)