The figure shows a metallic plate of uniform thickness and density. The value of `l` in terms of L so that the centre of mass of the system lies at the interface of the triangular and rectangular portion is

In the figure, the L- shaped shaded piece is cut from a metal plate of uniform thickness. The point that corresponding to the center of mass of the L- shapped piece is :-

In the figure, the L- shaped shaded piece is cut from a metal plate of uniform thickness. The point that corresponding to the center of mass of the L- shapped piece is :-

In the figure, the L- shaped shaded piece is cut from a metal plate of uniform thickness. The point that corresponding to the center of mass of the L- shapped piece is :-

Figure shows a square plate of uniform thickness and side length sqrt 2 m . One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is

A uniform disc of diameter R/2 is put over another uniform disc of diameter R of same thickness and density. The peripheries of the two disc touch each other. The centre of mass of the system from centre of big disc is

The figure shows a square metal plate of side l from which a square plate of side a has been cut as shown in the figure. Find the ratio (a//l) so that the centre of mass of the remaining L-shaped plate coincides with the point A

Show that the centre of mass of uniform rod of mass M and length L lies at the middle point of the rod.