The Value of `x` is `|[x,2,1],[3,x,-2],[1,3,1]|=5`

The value of x so that [[1,x,1]][[1,3,2] , [0,5,1] , [0,3,2]][[1], [1], [x]]=0 is

Find the value of x, if [1x1][{:(1,3,2),(2,5,1),(15,3,2):}][{:(1),(2),(x):}]=O.

Find the value of x, if [1x1][{:(1,3,2),(2,5,1),(15,3,2):}][{:(1),(2),(x):}]=0

Find the value of x such that [1,x,1][[1,2,3],[4,5,6],[3,2,5]][[1],[-2],[3]]=O

Find the value of x, if |[(3+x), 5, 2],[1, (7+x), 6], [2, 5, (3+x)]| = 0

If |[x^(3)+1,2x,1],[0,5+x,-3],[x-1,x^(2),2]|+|[3,2,1],[-1,5,-2],[0,4,6]|= ax^(5)+bx^(4)+cx^(3)+dx^(2)+ex+f is true for all x in R, then the value of f is

The value of (x , y) if 5^(x) + 3^(y) = 8,5^(x-1) + 3^(y-1) = 2 is :

Let tan^(-1)y=tan^(-1)x+tan^(-1)((2x)/(1-x^(2))) where |x|<(1)/(sqrt(3))* Then a value of y is : (1)(3x-x^(3))/(1-3x^(2))(2)(3x+x^(3))/(1-3x^(2))(3)(3x-x^(3))/(1+3x^(2))(4)(3x+x^(3))/(1+3x^(2))

The value of 3x^2 - 5x + 3 " when " x = 1 is