If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for `._(4)Be^9` (mass=9.012 amu) would be-

If the mass of a proton, m_(p)=1.008u mass of a neutron m_(n)=1.009u ,then the binding energy of an alpha -particle of mass 4.003 u will be (Mev) (take 1a.m.u=931MeV)

If the mass defect of ""_(4)^(9)X is 0.09 a.m.u. then the binding energy per nucleon is (1 a.m.u= 931.5 MeV)

If the mass defect of ""_(4)^(9)X is a.m.u., then binding energy per nucleon is (1 a.m.u. = 931.5 MeV):

If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)

The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?

The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?

The atomic mass of F^(19) is 18.9984 m_(u) . If the masses of proton and neutron are 1.0078 m_(u) and .0087 m_(u) . Respectively, calculate the binding energy per nucleon (ignore the mass of electrons). (1 m_(u) = 931) MeV)

The atomic mass of F^(19) is 18.9984 m_(u) . If the masses of proton and neutron are 1.0078 m_(u) and .0087 m_(u) . Respectively, calculate the binding energy per nucleon (ignore the mass of electrons). (1 m_(u) = 931) MeV)