Find the equation of the ellipse in the form `((x-h)^2)/a^2+((y-k)^2)/b^2=1`. Given the following data.
Centre(2,-1) , e=`1/2`, length of latus rectum 4.

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1 . Given the following data. Centre(0,-3),e= 2/3 , semi -minor axis =5.

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1 . Given the following data. Centre(2,-1) one end of major axis (2,-5), e= 1/3 .

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1 . Given the following data. Centre(4,-1) one end of major axis is (-1,-1), and passing through (8,0).

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1(a>b) , given : centre (2,3) and whose axes are 8 and 6.

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1(a>b) , given : centre (2,5), major axis is 10, semi minor axis is 2.

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1(a>b) , given : centre (3,4), passing through (-1,0) and major axis is 16.

Find the equation of the ellipse in the form ((x-h)^2)/a^2+((y-k)^2)/b^2=1(a>b) , given : vertices (2,-2) and (2,-4) and eccentricity is 1/3 and distance between the foci is 4.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.