Relative decrease in vapour pressure in vapour pressure of an aqueous solution NaCI is 0.1067, Number of moles of NaCI present in 180 g `H_(2)O` is:

Relative decrease in vapour pressure of an aqueous NaCl is 0.167 . Number of moles of NaCl present in 180g of H_(2)O is:

Relative decrease in vapour pressure of an aqueous NaCl is 0.167 . Number of moles of NaCl present in 180g of H_(2)O is:

Relative lowering in vapour pressure of an aqueous NaCl solution is 1/6. What is the number of moles of NaCl present in 180g H_(2)O

Relative decrease in vapour pressure of an aqueous NaCl is 0.181. Number of moles of NaCl present in 180g of H_2O is (consider 100% dissociation of NaCl)

Calculate relative lowering of vapour pressure of 0.161 molal aqueous solution

Calculate relative lowering of vapour pressure of 0.161 molal aqueous solution