solve `D^(4)+8D^(2)+16=0`

solve : 16x^(4)- 28x^(2) - 8 = 0

Solve 8x^(2)-16x=0 .

Solve 8x^(2)-16x=0 .

solve x^(2)=(0.2)^(log)((1)/(4)+(1)/(8)+(1)/(16)...) base sqrt(5)

If the circle x^(2)+y^(2)+2ax+8y+16=0 touch x-a xi s, then the value of a is +-16 (b) +-4(c)+-8(d)+-1

If the perimeter of a square is 16cm, then its area is 4cm^(2)(b)8cm^(2)16cm^(2)(d)12cm^(2)

The positive value of k for which the equation x^2+k x+64=0 and x^2-8x+k=0 will both have real roots, is (a)4 (b) 8 (c) 12 (d) 16

Solve 16x^(2)+4=0

Solve 16x^(2)+4=0

If a>0, then least value of (a^(3)+a^(2)+a+1)^(2) is (a)64a^(2)(b)16a^(4)(c)16a^(3) (d)d.none of these