The resistance of a `1N` solution of salt is `50 Omega`. Calculate the equivalent conductance of the solution, if the two platinum electrodes in solution are 2.1 cm apart and each having an area of `4.2 cm^(2)`.

The resistance of a 0.5 N solution of salt is 20 Omega .Calculate the equivalent conductance of the solution if the platinum electrodes are 1.5 cm apart and each having an area of 3.0cm^(2) .

The resistance of aN//10KCI solution is 245 Omega . Calculate the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each haveing an area of 7.0 sq.cm .

The resistance of an N//10 KCl solution is 245 ohms . Calculate the equivalent conducatnce of the solution id the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq.cm.

The resistance of a N//10 KCI solution is 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq cm.

The resistance of a N//10 KCI solution is 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq cm.

The resistance of a N//10 KCI solution is 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq cm.

The resistance of N//5 solution of an electrolyte in a cell was found to be 45 ohm. Calculate the equivalent conductance of the solution if the electrodes in a cell are 2.2 cm apart and have an area of 3.8 equiv. cm.

The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 Omega . Calculate the equivalent conductance of the solution if the electrodes in the cell were 2 cm part and each had an area of 3.5 sq. cm.