A force `vec F=(6 hati -8 hatj)N`, acts on a particle and displaces it over `4 m` along the X-axis and `6 m` along the Y-axis. The work done during the total displacement is

A constant force vecA =-hati +2hatj+3hatkN acts on a body, and shifts it 4 m along z-axis and then 3m along y-axis. Work done by vecF will be

A force vecF=hati+2hatj+3hatkN acts on a particle and displaces it through a distances vecs=4hati+6hatjm calculate the work done.

A force vecF = (5 hati + 4 hatj)N acts on a body and produces a displacement vecs = (6 hati - 5 hatj + 3 hatk)m . The work done will be

A force vecF=(5hati+3hatj)N is applied over a particle which displaces it from its original position to the point vecs=S(2hati-1hatj)m . The work done on the particle is

A force vecF=(5hati+3hatj)N is applied over a particle which displaces it from its original position to the point vecs=S(2hati-1hatj)m . The work done on the particle is

A force vecF=(5hati+3hatj+2hatk)N is applied over a particle which displaces it from its origin to the point vecr=(2hati-hatj) m. The work done on the particle in joules is :

A force oversetrightarrowF=hati+5hatj+7hatk acts on a particle and displaces it through oversetrightarrows=6hati+9hatk . Caldulate the work done if the force is in newton and displacement in metre.

When a force vector vecF=(hati+2hatj+hatk) N acts on a body and produces a displacement of vecS=(4hati+hatj+7hatk) m, then the work done is