A block of `150kg` is placed on an inclined plane withh an angle of `60^(@)`. Calculate of the weight parallel to the inclined plane.

A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

A block of mass 10 kg is placed on an inclined plane when the angle of inclination is 30^(@) . The block just begins to slide down the plane. The force of static friction is

The acceleration of 10 kg block on the inclined plane is

A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

A block of mass 10 kg is placed on rough inclined plane of inclination angle 37^(@) .Coefficient of friction between block & plane is 0*8 , find minimum magnitude of F so that block remains at rest .