A spherical balloon is being inflated so that its volume increase uniformaly at the rate of `40 cm^(3)//"minute"`. The rate of increase in its surface area when the radius is 8 cm, is

The spherical ballon is being inflated so that its volume increases uniformly at the rate of 40 cubic cm per minute. The rate of increase in the surface as when the radius is 8 cm is

A balloon is pumped at the rate of a cm^3 /minute. The rate of increase of its surface area when the radius is b cm , is

A spherical balloon is being inflated so that itsvolume increases uniformly at the rate of 40cm3/min .How fast is its surface area increasing when the radius is 8cm? Find how much approximately the radius will increase during the next (1)/(2) minute.

The volume of a sphere is increasing at the rate of 1200 c.cm/sec. The rate of increase in its surface area when the radius is 10 cm is

A spherical balloon is being inflated so that its volume increase uniformly at the rate of 40c(m^(3))/(min). How much the radius will increases during the next 1/2 minute ?

A balloon is pumped at the rate of 2 cm^3// minute. Write the rate of increase of the surface area, when the radius is 0.5 cm.

The volume of a sphere increase at the rate of 20cm^(3)//sec . Find the rate of change of its surface area when its radius is 5 cm

A spherical balloon is being inflated so that its volume increase uniformly at the rate of 40(cm)^3/min . How much the radius will increases during the next 1/2 minute,if initial radius is 8cm. ?