Two particles are projected from the same point with the same speed at different angles `theta_1` & `theta_2` to the horizontal. They have the same range. Their times of flight are `t_1` & `t_2` respectily

Two particles are projected from the same point with the same speed at different angles theta_1 & theta_2 to the horizontal. They have the same range. Their times of flight are t_1 & t_2 respectfully

Two particles are projected from the same point with the same speed, at different angles theta_1 and theta_2 to the horizontal. Their times of flight are t_1 and t_2 respectively and they have the same horizontal range. Then the incorrect relation is

Two particles are projected from the same point with the same speed at different angles theta_(1) and theta_(2) to the horizontal. If their respectively times of flights are T_(1) and T_(2) and horizontal ranges are same then (a) theta_(1) + theta_(2) = 90^(@) (b) T_(1) = T_(2) tan theta_(1) (c) T_(1) = T_(2) tan theta_(2) (d) T_(1) sin theta_(2) = T_(2) sin theta_(1)

Two particles are projected from the same point with the same speed at different angles theta_(1) and theta_(2) to the horizontal. If their respective times of flights are T_(1) and T_(2) and horizontal ranges are same then a) theta_(1)+theta_(2)=90^(@) , b) T_(1) =T_(2)tan theta_(1) c. T_(1) =T_(2)tan theta_(2) , d) T_(1)sin theta_(2)=T_(2)sin theta_(1)

Two bodies are projected at angle theta and ( 90 -theta ) to the horizontal with the same speed. Find the ration of their time of flight.