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If the difference of the roots of the equation, `x^2+p x+q=0` be unity, then `(p^2+4q^2)` equals to: `(1+1q)^2` b. `(1-2q)^2` c. `4(p-q)^2` d. `2(p-q)^2`

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If the difference of the roots of the question ,x^(2)+px+q=0"be unity, then"(p^(2)+4q^(2)) equals to :

If the difference of the roots of the equation,x^(2)+px+q=0 be unity,then (p^(2)+4q^(2)) equals to: (1+1q)^(2) b.(1-2q)^(2) c.4(p-q)^(2) d.2(p-q)^(2)

If the difference of the roots of the equation,x^(2)+px+q=0 be unity,then (p^(2)+4q^(2)) equal to: (1-2q)^(2)(b)(1-2q)^(2)4(p-q)^(2)(d)2(p-q)^(2)

If difference of roots of the equation x^(2)-px+q=0 is 1, then p^(2)+4q^(2) equals-

If p and q are roots of the equation 2x^2-7x+3 then p^2+q^2=

If the difference of the roots of equation x^(2)+2px+q=0 and x^(2)+2qx+p=0 are equal than prove that p+q+1=0.(p!=q)

If the difference of the roots of x^(2)-px+q=0 is unity,then p^(2)+4q=1b .p^(2)-4q=1c*p^(2)+4q^(2)=(1+2q)^(2)d4p^(2)+q^(2)=(1+2p)^(2)

If a + b ne 0 and the roots of x^(2) - px + q = 0 differ by -1, then p^(2) - 4q equals :

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