If `n^(2)-11n+24=0` is satisfied by `n_(1)&n_(2)` where `n_(2)gtn_(1)` then

If n^(2)-11n+24=0 is satisfied by n_(1)&n_(2) where n_(2)>n_(1) then

If electrons in H-likes species jump, from n_(3) to n_(1) emitting photon of wavelength lambda , from n_(3) to intermediate orbit n_(2)[n_(3)gtn_(2)gtn_(1)] emits photon with wavelength lambda_(1) & from n_(2) to n_(1) emits photon with wavelength lambda_(2) then correct option is :

Find the integral solution for n_(1)n_(2)=2n_(1)-n_(2), " where " n_(1),n_(2) in "integer" .

In case of hydrogen spectrum wave number is given by barv=R_(H)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))] where n_(1)gtn_(2) {:(,"ColumnI",,"ColumnII"),((A),"Lyman series",(P),n_(2)=2),((B),"Balmer series",(Q),n_(2)=3),((C),"Pfund series",(R),n_(2)=6),((D),"Brackett series",(S),n_(2)=5):}

The sum S_(n) where T_(n)=(-1)^(n)(n^(2)+n+1)/(n!) is

The value of (n!)^(n) if n+(n-1)+(n-2)=n(n-1)(n-2) where n^(3)>9, a positive number is

If 3*n_(1)-n_(2)P_(2)=^(n_(1)+n_(2))P_(2)=90 then the ordered pair (n_(1),n_(2)) is

If (n+2C_(6))/(n-2P_(2))=11, then n satisfies the equation: