The change required to deposite 9 g of Al from `Al^(3+)` solution is (at. Wt. of Al = 27.0) :

The number of moles of electrons required to deposite 36 g of Al from an aqueous solution of Al(NO_(3))_(3) , is (At. wt. of Al = 27)

The number of faradays required to deposit 27gm ‘Al’ from a solution of AlCl_3 will be

The number of electrons required to deposit 1 g atom of Al(at. Wt.=27) from a solution of AlCI_3 are :

The amount of electricity required to deposit one mole of Al from a solution of AlCl_(3) will be

The charge required to deposit 40.5 g of Al (atomic mass 27 g ) from fused Al _ 2 ( SO _ 4 ) _ 3 is