If `m^2-n^2= 7`, where `m, n epsilon Z`, then number of ordered pairs (m,n) is

If m^(2)-n^(2)=7, where m,n varepsilon Z, then number of ordered pairs (m,n) is

The natural numbers ware not sufficient to deal with various equations that mathematicians encountered so some new sets of numbers were defined Ehole numbers (W) = {0,1,2,3,4,……….} Integers (Z or I) = (……, -3,-2,-1,1,0,2,3,4,……} Even integers :- Intigers divisible by 2, they are expressed as 2n n in Z. odd Integers :- Integers not divisible by 2, they are expressed as 2n+1or 2n-1,ninZ. If m^(2)-n^(2)=7, where m, n in Z, then number of ordered pairs (m,n) is

If m and n are +ve integers such that (m+n)P_(2)=90 and m-np_(2)=30, the number of ordered pairs (m,n) of such integers is

If m and n are integers satisfying (m-8)(m-10)=2^(n) ,then the number of ordered pairs (m,n) is

If m=n^(2)-n , where n is an integer , then m^(2)-2m is divisible by