The ratio of `pH` of solution `(1)` containing 1 mole of` CH_(3)COONa` and 1 mole of `HCl` and solution `(II)` containing 1 mole of `CH_(3)COONa` and 1 mole of acetic acid in one litre is `:`

The ratio of the pH of solution (I) containing 1 mol of CH_(3)COONa and 1 mol of HCl in 1L, and solution (II) containing 1 mol of CH_(3)COONa and 1 mol of CH_(3)COOH in 1L is

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The ratio of pH of solution (I) containing 1 mole to pH of solution (II) containing 1 mole of CH_(3)COONa and 1 mole of acetic in one litre is :

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. Calculate the ratio of pH of a solution containing 1 mole of CH_3COONa + 1 mole of HCl per litre and of other solution containing 1 mole CH_3COONa + 1 mole of acetic acid per litre

Calculate the ratio of pH of a solution containing 1 mole CH_3COONa + 1 mole of HCI per litre and of the other solution containing 1 mole of CH_3COONa + 1 mole of CH_3COOH per litre

a. Calculate the ratio of pH of a solution continaing 1mol . Of CH_(3)COONa +1 mol of HC1 per litre and of other solution containing 1mol of CH_(3)COONa + 1mol of CH_(3)COOH per litre. b. A 0.1M solution of weak acid HA is 1% dissociated at 298k . what is its K_(a) ? what will be the new degree of dissociation of HA and pH when 0.2M of NaA is added to it.

One mole of CH_(4) contains