`C(13,5)=`

C(13,4)=

If the ellipse (x^2)/(a^2-7)+(y^2)/(13-5a)=1 is inscribed in a square of side length sqrt(2)a , then a is equal to (a) 6/5 (b) (-oo,-sqrt(7))uu(sqrt(7),(13)/5) (c) (-oo,-sqrt(7))uu((13)/5,sqrt(7),) (d)no such a exists

Using section formula , show that the points A(7,-5),B(9,-3) and C(13,1) are colliner.

Let A = {10,11,12,13,14} , B = {0,1,2,3,5} and f_(i) : A rarr B , I = 1, 2,3, state the type of function for the following (give reason ) : (i) f_(1) = {(10,1),(11,2),(12,3),(13,5),(14,3)} f_(2) {(10,1),(11,1),(12,1),(13,1),(14,1)} (iii) f_(3) = {(10,0),(11,1),(12,2),(13,3),(14,5)}

If the middle points of the sides B C ,C A , and A B of triangle A B C are (1,3),(5,7), and (-5,7), respectively, then find the equation of the side A Bdot

In a triangle A B C ,A=(alpha,beta)B=(2,3),a n dC=(1,3)dot Point A lies on line y=2x+3, where alpha in Idot The area of DeltaA B C , , is such that [Delta]=5 . The possible coordinates of A are (where [.] represents greatest integer function). (a) (2,3) (b) (5,13) (c) (-5,-7) (d) (-3,-5)

A B C is an isosceles triangle. If the coordinates of the base are B(1,3) and C(-2,7) , the coordinates of vertex A can be (a) (1,6) (b) (-1/2,5) (c) (5/6,6) (d) none of these

Prove that 2 cos""(pi)/(13)cos""(9pi)/(13)+cos""(3pi)/(13)+cos""(5pi)/(13)=0