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If s(n) = sum(r = 0)^(n) 1/(""^(n)C(r)) ...

If `s_(n) = sum_(r = 0)^(n) 1/(""^(n)C_(r))` and `t_(n) = sum _(r = 0)^(n) r/(""^(n)C_(r))`,then `t_(n)/s_(n)` is equal to

A

`n - 1`

B

`1/2n - 1`

C

`1/2n`

D

`(2n -1)/2`

Text Solution

Verified by Experts

The correct Answer is:
C
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