Home
Class 12
MATHS
Find the area of the triangle formed by ...

Find the area of the triangle formed by the lines joining the vertex of the parabola `x^2 = 12y` to the ends of its latus rectum.

Text Solution

Verified by Experts

The correct Answer is:
18 sq. cm
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NEW JOYTHI PUBLICATION|Exercise EXERCISE - CIRCLE|18 Videos

  • CONIC SECTIONS

    NEW JOYTHI PUBLICATION|Exercise EXERCISE - PARABOLA|19 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NEW JOYTHI PUBLICATION|Exercise QUESTIONS FROM COMPETITIVE EXAMS|194 Videos

  • DIFFERENTIAL EQUATIONS

    NEW JOYTHI PUBLICATION|Exercise OBJECTIVE TYPE QUESTION|19 Videos

Similar Questions

Explore conceptually related problems

Find the area of the triangle found by the lines joining the vertex of the parabola x^(2) -36y to the ends of the latus rectum.

Find the vertex of the parabola x^2=2(2x+y)

The area of the triangle formed by the tangent and the normal to the parabola y^2=4a x , both drawn at the same end of the latus rectum, and the axis of the parabola is 2sqrt(2)a^2 (b) 2a^2 4a^2 (d) none of these

Find the equations of normal to the parabola y^2=4a x at the ends of the latus rectum.

Find the area of the region bounded by the line y = 2x + 5 and the parabola y = x^(2) - 2x

The area bounded by the parabola y^(2) = x and its latus rectum is

Find the area of the triangle formed by the line x+y=3 and the angle bisectors of the pair of lines x^2-y^2+4y-4=0

Find the area of the triangle formed by the lines y - x = 0, x + y = 0 " and " x - k = 0 .