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The ends of diameter of a circle are (2,...

The ends of diameter of a circle are `(2,3) and (6,5)`. The centre of the circle is

A

`(3,0)`

B

`(8,8)`

C

`(4,4)`

D

`(2,2)`

Text Solution

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The correct Answer is:
C
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NEW JOYTHI PUBLICATION-CONIC SECTIONS -EXERCISE - CIRCLE
  1. The centre of the circle x^2 + y^2 + x + y - 15 = 0 is

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  2. If one end of a diameter of a circle is (3,5) and the centre is (2,3) ...

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  3. If one end of a diameter of a circle2x^2 + 2y^2 - 4x - 8y + 2 = 0 is (...

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  4. The circle x^2 + y^2 - 3x - 4y + 2 = 0 cuts the x axis at the points

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  5. The ends of diameter of a circle are (2,3) and (6,5). The centre of th...

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  6. The circle x^2 + y^2 - 4x + 6y + c = 0 touches x axis if

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  7. The circle x^2 + y^2 - 4x + 6y + c = 0 touches x axis if

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  8. The circle x^2 + y^2 - 8x + 4y + 4 = 0 toches

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  9. The equation of a circle of radius r and touching both the axes is

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  10. If (alpha, beta) is the centre of a circle passing through the origin ...

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  11. The circle x^2 + y^2 - 8x + 4y + 4 = 0 toches

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  12. The intercept on the line y = x by the circel x^2 + y^2 - 2x = 0 is AB...

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  13. Two vertices of an equilateral triangle are (-1,0) and (1,0) then its ...

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  14. A circle touches the y axis at (0,2) and its x intercept equal to 3 u...

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  15. The lines 2x + 3y + 1 = 0 and 3x - y - 4 = 0 lie along the diameters o...

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  16. The radius of the circle passing through the point (6,2) and two of wh...

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  17. The radius of the circle having centre at (2,1) whose one of the chord...

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  18. The circle x^2 + y^2 - 8x + 4y + 4 = 0 toches

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