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Two vertices of an equilateral triangle ...

Two vertices of an equilateral triangle are `(-1,0) and (1,0)` then its circumcircle is

A

`x^2 + (y - 1/(sqrt3))^2 = 4/3`

B

`x^2 + (y + 1/(sqrt3))^2 = 1/3`

C

`x^2 + (y - 1/(sqrt3))^2 + 4/9 = 0`

D

`x^2 + y^2 = 4/3`

Text Solution

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The correct Answer is:
A
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NEW JOYTHI PUBLICATION-CONIC SECTIONS -EXERCISE - CIRCLE
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