Home
Class 12
MATHS
The vertex of the parabola y^2 = 4x + 4y...

The vertex of the parabola `y^2 = 4x + 4y` is

A

`(1,-2)`

B

`(-1,2)`

C

`(2,1)`

D

`(-2, 1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NEW JOYTHI PUBLICATION|Exercise EXERCISE - ELLIPSE|18 Videos
  • CONIC SECTIONS

    NEW JOYTHI PUBLICATION|Exercise EXERCISE - HYPERBOLA|9 Videos
  • CONIC SECTIONS

    NEW JOYTHI PUBLICATION|Exercise EXERCISE - CIRCLE|18 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NEW JOYTHI PUBLICATION|Exercise QUESTIONS FROM COMPETITIVE EXAMS|194 Videos
  • DIFFERENTIAL EQUATIONS

    NEW JOYTHI PUBLICATION|Exercise OBJECTIVE TYPE QUESTION|19 Videos

Similar Questions

Explore conceptually related problems

The vertex of the parabola y^2 + 4x = 0 is

A P is perpendicular to P B , where A is the vertex of the parabola y^2=4x and P is on the parabola. B is on the axis of the parabola. Then find the locus of the centroid of P A Bdot

Through the vertex O of the parabola y^(2) = 4ax , a perpendicular is drawn to any tangent meeting it at P and the parabola at Q. Then OP, 2a and OQ are in

A square has one vertex at the vertex of the parabola y^2=4a x and the diagonal through the vertex lies along the axis of the parabola. If the ends of the other diagonal lie on the parabola, the coordinates of the vertices of the square are (a) (4a ,4a) (b) (4a ,-4a) (c) (0,0) (d) (8a ,0)

If (a , b) is the midpoint of a chord passing through the vertex of the parabola y^2=4x , then a=2b (b) a^2=2b a^2=2b (d) 2a=b^2

If (a ,b) is the midpoint of a chord passing through the vertex of the parabola y^2=4x, then prove that 2a=b^2

The vertex of the parabola x^(2)=8y-1 is :

If the area of the triangle whose one vertex is at the vertex of the parabola, y^(2) + 4 (x - a^(2)) = 0 and the other two vertices are the points of intersection of the parabola and Y-axis, is 250 sq units, then a value of 'a' is

If chord BC subtends right angle at the vertex A of the parabola y^(2)=4x with AB=sqrt(5) then find the area of triangle ABC.

NEW JOYTHI PUBLICATION-CONIC SECTIONS -EXERCISE - PARABOLA
  1. The vertex of the parabola y^2 + 4x = 0 is

    Text Solution

    |

  2. The focus of the parabola y^2 = 20 x is

    Text Solution

    |

  3. The axis of the parabola y^2 = x is the line

    Text Solution

    |

  4. The latus rectum of the parabola y^2 = 11x is of length

    Text Solution

    |

  5. If (3,0) is the focus and y axis is the tangent at vertex. Then the eq...

    Text Solution

    |

  6. If the parabola y^2 = ax passes through (3,2) then the focus is

    Text Solution

    |

  7. Equation of the parabola with focus (-4,0) and vertex at the origin is

    Text Solution

    |

  8. The equation of the directrix of the parabola x^2 = 28y = 0 is

    Text Solution

    |

  9. The vertex of the parabola y^2 = 4x + 4y is

    Text Solution

    |

  10. The focus of the parabola 4y^2 + 12x - 12y + 39 = 0 is

    Text Solution

    |

  11. Axis of the parabola x^2 - 3y - 6x + 6 = 0 is

    Text Solution

    |

  12. The equation of the parabola with vertex at (0,0) , axis along y axis ...

    Text Solution

    |

  13. The length of latus rectum of the parabola 4y^2 + 2x - 20y + 17 = 0 is

    Text Solution

    |

  14. The length of the latus rectum of the parabola x^2 - 4x - 8y + 12 = 0 ...

    Text Solution

    |

  15. The equation of the directrix of the parabola y^2 + 4y + 4x + 2 = 0 is

    Text Solution

    |

  16. The equation of the parabola with its vertex at (1,1) and focus at (3,...

    Text Solution

    |

  17. Equation of the parabola with focus (3,0) and the directrix x + 3 = 0 ...

    Text Solution

    |

  18. If (0,6) and (0,3) are respectively the vertex and focus of a parabola...

    Text Solution

    |

  19. The line x - y + 2 = 0 touches the parabola y^2 = 8x at the point

    Text Solution

    |