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The cartesian equation of a line is (x-5...

The cartesian equation of a line is `(x-5)/3=(y+4)/7=(z-6)/2`. Write its vector form.

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NEW JOYTHI PUBLICATION-THREE DIMENSIONAL GEOMETRY-Ncert TextBook Exercise 11.2
  1. Show that the three lines with direction cosines 12/13,(-3)/13,(-4)/13...

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  2. Show that the line through the points (1,-1,2) ,(3,4,-2) is perpendicu...

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  3. Show that the line through the points (4,7,8),(2,3,4) is parallel to t...

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  4. Find the equation of the line which passes through the point (1,2,3) a...

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  5. Find the equation of the line in vector and in cartesian form that pas...

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  6. Find the cartesian equation of the line which passes through the point...

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  7. The cartesian equation of a line is (x-5)/3=(y+4)/7=(z-6)/2. Write its...

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  8. Find the vector and the cartesian equations of the lines that pass thr...

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  9. Find the vector and the cartesian equations of the line that passes th...

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  10. Find the angle between the following pairs of lines : .vecr=3hati+hatj...

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  11. Find the angle between the following pairs of lines : i.(x-2)/2=(y-...

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  12. Find the values of p so that the lines (1-x)/3 =(7y-14)/(2p)=(z-3)/2...

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  13. Show that the lines (x-5)/7=(y+2)/(-5)=z/1 and x/1=y/2=z/3 are perpend...

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  14. Find the shortest distance between the lines vecr=(hati+2hatj+hatk)+la...

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  15. Find the shortest distance between the lines (x+1)/7=(y+1)/(-6) =(z+1)...

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  16. Find the shortest distance between the lines whose vector equations ar...

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  17. Find the shortest distance between the lines whose vector equations ar...

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