Find the intercepts cut off by the plane 2x+y-z=5.

Find the intercept cut off by the plane vec(r)=(6hat(i)+4hat(j)-3hat(k))=12 on the coordinate axes.

Find the unit normal vectors to the plane 2x+y-2z=5 .

Find the equation of the plane containing the line of intersection of the planes x + y + z - 6 = 0 and 2x + 3y + 4z + 5 = 0 and passing through the point (1,1,1)

Reduce the equation of line x-y+2z=5a d n3x+y+z=6 in symmetrical form. Or Find the line of intersection of planes x-y+2z=5a n d3x+y+z=6.

The x and y intercepts of the line 2x+5y=10 are :

Find the distance of the plane 2x-y-2z-9=0 from the origin.

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0

Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

Find the point intersection of the line x-1=(y)/(2)=z+1" with the plane "2x-y+2z=2. Also, find the angle between the line and the plane.