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The vector equation of a plane which is ...

The vector equation of a plane which is at a distance of `6/sqrt29` from the origin and its normal vector from the origin is `2hati-3hatj+4hatk` is

A

`vecr.(2hati-3hatj+4hatk)=6/sqrt29`

B

`vecr.(2/sqrt29 hati-3/sqrt29 hatj+4/sqrt29hatk)=6/sqrt29`

C

both (a) and (b)

D

none of these

Text Solution

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The correct Answer is:
B
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