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The angle theta between the line vecr=ve...

The angle `theta` between the line `vecr=veca+lambdavecb` and the plane `vecr.hatn=d` is given by

A

`sin^(-1)((vecb.hatn)/(|vecb|.|vecn|))`

B

`cos^(-1)((vecb.hatn)/(|vecb|.|vecn|))`

C

`sin^(-1)((veca.hatn)/(|veca|))`

D

`cos^(-1) ((veca.hatn)/(|veca|))`

Text Solution

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The correct Answer is:
A
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