The ammonia molecule has a permanent electric dipole moment of 1.47 D where D is the debye unit and `1D=3.34 xx 10^(-30)Cm`. Calculate the electric potential due to the ammonia molecule at a point distant 30 nm away along the dipole axis.

Explanation

Data supplied,
Dipole moment (p) `=1.47 xx 3.34 xx 10^(-30) C.m, r=30 xx 10^(-9) m =3 xx 10^(-8)m`
Being along the axis `theta=0, therefore cos theta=1`
Potential `V=(1)/(4epsi_(0)). (p cos theta)/(r^(2))=(9 xx 10^(9) xx 1.47 xx 3.34 xx 10^(-30) xx 1)/(9 xx 10^(-16))=4.91 xx 10^(-5)V =49.1muV`