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If A 250V capacitors of C(1)=2muF=2 xx 1...

If A 250V capacitors of `C_(1)=2muF=2 xx 10^(-6)F" "C_(2)=5muF=5 xx 10^(-6)F` then find charge and energy stored in each capacitor.

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V=250V `C_(1)=2muF 2 xx 10^(-6)F " "C_(2)=5muF=5 xx 10^(-6)F`
Charge in `C_(1), Q_(1)=C_(1) V=2 xx 10^(-6) xx250 =0.5 xx 10^(-3)C`
Energy stored in `C_(1)=1/2 C_(1) V^(2)=1/2 xx 2 xx 10^(-6) xx (250)^(2)=0.0625 J`
Charge in
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NEW JOYTHI PUBLICATION-ELECTROSTATIC POTENTIAL AND CAPACITANCE-Competitive Exam Corner
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