A regular hexagon of side 10cm has a charge `5muC` at each of its vertices. Calculation the potential at the centre of the hexagon.

Explanation

If .q. is the charge, potential at .O. is `9 xx 10^(9) xx q/a`, where .a. is the side of the exagon.
Total potential `=(6 xx q xx 9 xx 10^(9))/(a)`
`=(9 xx 10^(9) xx 6 xx 5 xx 10^(-6))/(10 xx 10^(-2))=2.7 xx 10^(6)V or 2.7MV`