What is the area of plates of 2F parallel capacitor, given that the separation between the plates is 0.5 cm? [You will realise from your answer why ordinary capacitors are in the range of `muF` or less. However, electrolytic capacitors do have a much larger capacitance (0.1F) because of very minute separation between the conductors.

Explanation

`A=?, C=2F, d=0.5 xx 10^(-2)m`
`2=(8.85 xx A xx 10^(-12))/(0.5 xx 10^(-2))`
`A=(2 xx 10^(10))/(17.7) =1.13 xx 10^(9) m^(2)=1.13 xx 10^(3) xx (10^(3))^(2) m^(2)=1130(km)^(2)`