Home
Class 12
PHYSICS
What is the electric field in between th...

What is the electric field in between the plates of the capacitor, if `sigma` is the surface charge density?

Text Solution

Verified by Experts

`E=(sigma)/(epsi_(0))`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NEW JOYTHI PUBLICATION|Exercise Previous Year Questions|2 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NEW JOYTHI PUBLICATION|Exercise Competitive Exam Corner|22 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NEW JOYTHI PUBLICATION|Exercise Practice Problems For Self Assessment|23 Videos
  • ELECTROMAGNETIC WAVES

    NEW JOYTHI PUBLICATION|Exercise COMPETITIVE EXAM CORNER|16 Videos
  • MAGNETISM AND MATTER

    NEW JOYTHI PUBLICATION|Exercise COMPETITIVE EXAM CORNER|13 Videos

Similar Questions

Explore conceptually related problems

What is the electric field in between the plates of a capacitor in the presence of adielectric medium?

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_(2)-E_(1)).hatn=sigma/epsi_(0) where hatn is a unit vector normal to the surface at a point and sigma is the surface charge density at that point. (The direction of hatn is from side 1 to side 2). Hence show that just outside a conductor, the electric field is (sigma hatn)/(epsi_(0)) . (b) Show that the tangetial component of electrostatic field field is continuous from one side of a charged surface to another. [Hint: For (a), use Gauss law. For (b) use the fact that work done by electrostatic field on a a closed loop is zero].

A parallel plate capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates

Find the force of attraction between the plates of a parallel plate capacitor.

a. A closed loop is held stationary int eh magnetic field between the north and south poles of two permanent magnets held fixed. Can we hope to generate current in the loop by using very strong magnets? b. A closed loop move normal to the constant electric field between the plates of a large capacitor. Is a current induced in the loop (i) when it is wholly inside the region between the capacitor plates (ii) when it is partially outside the plates of the capacitor? The electric field is normal to the plane of the loop. c. A rectangular loop and a circular loop are moving out of a uniform magnetic field (region). (see fig.) to field-free region with a constant velocity v. In which loop do you expect the induced emf to be constant during the passage out of the field region? The field is normal to the loops. d. Predict the polarity of the capacitor in the situation described by the figure below.

The electric field between the plates of a parallel-plate capacitor of capacitance 2.0(mu)F drops to one third of its initial value in (4.4 mu)s when the plates are connected by a thin wire. Find the resistance of the wire.

Two large conducting plates X and Y. each having large surface area A (on one side), are placed parallel to each other as shown in figure (30-E7). The plate X is given a charge Q whereas the other is neutral. Find (a) the surface charge density at the inner surface of the plates X, (b) the electric field at a point to the left of the plates, (c) the electric field at a point in between the plates and (d) the electric field at a point to the right of the plates.

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2)QE , where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2 .

NEW JOYTHI PUBLICATION-ELECTROSTATIC POTENTIAL AND CAPACITANCE-Evaluation Questions And Answers
  1. What is the work done in increasing the charge from Q(1)" to "Q(1) +de...

    Text Solution

    |

  2. In which form and where is the energy of the capacitor stored?

    Text Solution

    |

  3. What is the electric field in between the plates of a capacitor in the...

    Text Solution

    |

  4. A capacitor of capacitance C is connected to a voltage source of p.d. ...

    Text Solution

    |

  5. What happens when a non polar molecule is placed in an external electr...

    Text Solution

    |

  6. What is the difference between a hydrogen molecule and HCI molecule?

    Text Solution

    |

  7. If the positive centre of charge coincides with negative centre of cha...

    Text Solution

    |

  8. Classify the following molecules into Polar and non-polar. (H2O, H2, N...

    Text Solution

    |

  9. What is the electric field in between the plates of the capacitor, if ...

    Text Solution

    |

  10. A conducting spherical shell of radius R has a charge Q. A small spher...

    Text Solution

    |

  11. Two copper spheres of radii, one hollow and the other solid are charge...

    Text Solution

    |

  12. Two capacitors when connected in series the effective capacity is 2muF...

    Text Solution

    |

  13. What is the capacity having a plate area A of the figure given below?

    Text Solution

    |

  14. Keeping the voltage of the charging source constant, what would be the...

    Text Solution

    |

  15. Four point charges are placed at the four corners of a square in the t...

    Text Solution

    |

  16. How much work is done in moving a 500 muC charge between two points on...

    Text Solution

    |

  17. Two dielectric slabs of dielectric constants K(1) and K(2) are filled ...

    Text Solution

    |

  18. An infinite number of charges, each of charge q, are located along the...

    Text Solution

    |

  19. Derive an expression for field intensity due to a uniformly charged ri...

    Text Solution

    |

  20. Two parallel plate capacitors X and Y have the same area of plates and...

    Text Solution

    |