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In the magnetic meridian of a certain pl...

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26 G and the dip angle is `60^@` . What is the magnetic field of the earth at this location ?

Text Solution

Verified by Experts

It is given that `H_E=0.26G`
`cos60^@=H_E/B_E`
`B_E=H_E/(cos60^@)=(0.26)/((1/2))=0.52G`
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