If the solenoid in is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25T is applied , what is the magnitude of torque on the solenoid when its axis makes an angle of `30^@` with the direction of applied field ? Given magnetic moment 0.6 JT −1 .

Explanation

B = 0.25 T , `theta =30^@`
`taumB sin theta=0.6xx0.25xxsin30=0.6xx0.25xx1/2=0.075Nm ` (or J)