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If the bar magnet in exercise 13 is turn...

If the bar magnet in exercise 13 is turned around by `180^@` where will the new null points be located ?

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On the equatorial line . Let d. be the corresponding distance . Since the two fields are equal to earth.s field
`10^(-7)xx(2m)/d^3=10^(-7)xxm/(d.^3)" ":.d.^3=(d^3)/2`
`d.="d"xx2^(-1/3)=14xx2^(-1/3)=11.1cm`
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