Home
Class 12
PHYSICS
A bar magnet of moment of inertia 9xx10^...

A bar magnet of moment of inertia `9xx10^(-5) "kg m"^2` placed in a vibration magnetometer and oscillating in a uniform magnetic field `16pi^2 xx 10^(-5) T` make 20 oscillations is 15 s . The magnetic moment of the magnet is

A

a) `3 Am^2`

B

b) `2 Am^2`

C

c) `5 Am^2`

D

d) `4 Am^2`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    NEW JOYTHI PUBLICATION|Exercise PREVIOUS YEAR QUESTIONS|3 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NEW JOYTHI PUBLICATION|Exercise Competitive Exam Corner|22 Videos
  • MOVING CHARGES AND MAGNETISM

    NEW JOYTHI PUBLICATION|Exercise COMPETITIVE EXAM CORNER|28 Videos

Similar Questions

Explore conceptually related problems

A magnetised needle of magnetic moment 3.6 xx 10^(-2) T^(-1) is placed at 30^(@) with the direction of uniform magnetic field of magnitude 2 xx 10^(-2)T . Calculate the torque acting on the needle.

A bar magnet of mass 100 g, length 7.0 cm, width 1.0 cm and height 0.50 cm takes pi/2 seconds to complete an oscillation in an oscillation magnetometer placed in a horizontal magnetic field of 25 muT . (a) Find the magnetic moment of the magnet. (b) If the magnet is put in the magnetometer with its 0.50cm edge horizontal, what would be the time period?

A bar magnet of length 1cm and cross-sectonal area 1.0 cm^2 produces a magnetic field of 1.5 xx 10^(-4) T at a point in end-on position at a distance 15cm away from the centre. (a) Find the magnetic moment M of the magnet. (b) Find the magnetization I of the magnet. (c) Find the magnetic field B at the centre of the magnet.

A bar magnet having a magnetic moment of 1.0 xx 10^4 J T^(-1) is free to rotate in a horizontal plane. A horizontal magnetic field B = 4 xx 10^(-5) T exists in the space. Find the work done in rotating the magnet slowly from a direction parallel to the field to a direction 60^@ from the field.

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

The frequency of oscillation of the magnet in an oscillation magnetometer in the earth's magnetic field is 40 oscillations per minute. A short bar magnet is placed to the north of the magnetometer, at a separation of 20cm from the oscillating magnet, with its north pole pointing towards north (figure). The frequency of oscillation is found to increase to 60 oscillations per minute. Calculate the magnetic moment of this short bar magnet. Horizonatl component of the earth's magnetic field is 24 muT .

Figure shows a short magnet executing small oscillations in an oscillation magnetometer in earth's magnetic field having horizontal component 24 muT . The time period of oscillation is 0.10 s . An upward electric current of 18 A is established in the vertical wire placed 20cm east of the magnet by closing the switch S . Find the new time period

A bar magnet takes pi/10 second to complete one oscillation in an oscillation magnetometer. The moment of inetria of the magnet about the axis of rotation is 1.2 xx 10^(-4) kg m^2 and the earth's horizontal magnetic field is 30 muT . Find the magentic moment of the magnet.

The combination of two bar magnets makes 10 oscillations per second in an oscillation magnetometer when like poles are tied together and 2 oscillations per second when unlike poles are tied together. Find the ratio of the magnetic moments of the magnets. Neglect any induced magnetism.

A magnet takes a minute to make 30 oscillations in a magnetic field. If the strength is doubled, then the time period of oscillation (in S) is