A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of `""_(29)^(63)Cu` atoms (of mass 62.92960 u).

Explanation

`BE = [{Zm_P + (A -Z)m_N]-M} 931 MeV`
`= [29 xx 1.007825 + (63 - 29) xx 1.008665 - 62.92960] 93] = 551.38 MeV`
Number of atoms in 63 g of Cu = `6.023 xx 10^(23)`
`:. ` Number of atoms in 3g of `Cu, n = (6.023 xx 10^23)/(63) xx 3 = 0.2868095 xx 10^(23)`
`:.` The energy requierd to separate all protons and neutrons ,
`E = BE xx n = 551.38 xx 0.2868095 xx 10^(23) = 1.58 xx 10^(25) MeV`