A particle with the potentila energy shown in the graph is moving to the right. It has 1.0J of kinetic energy at x=1.0m. Where the particle reverses its direction of motion?

A particle with total energy E moves in one direction in a region where, the potential energy is U The acceleration of the particle is zero, where,

A particle with total energy E moves in one direction in a region where, the potential energy is U The acceleration of the particle is zero, where,

A particle with total energy E moves in one direction in a region where, the potential energy is U The acceleration of the particle is zero, where,

A single conservative force F(x) acts on a particle that moves along the x - axis. The graph of the potential energy with x is given. At x=5m, the particle has a kinetic energy of 50 J and its potential energy is related to position 'x' as U=15+(x-3)^(2) Joule where x is in meter. Then:

For a particle moving on a straight lint the variation of acceleration with time is given by the graph as shown. Initially the particle was at rest. Then the corresponding kinetic energy of the particle versus time graph will be .

A particle of mass m has momentum p. What is its kinetic energy ?

A single conservative force F(x) acts on a 1.0-kg particle that moves along the x-axis. The potential energy U(x) is given by U(x)=20+(x-2)^2 where x is in meters. At x=5.0m , the particle has a kinetic energy of 20J . The maximum kinetic energy of the particle and the value of x at which maximum kinetic energy occurs are