Two metallic spehres each of mass `M` and radius `R` charged separately to `Q_(1)` and `Q_(2)` are at a distance `d` between their centres `(d gt2R)` The force between them will be

Two identical spheres each of mass M and radius R are separated by a distance 3R. The force of attraction between them is proportional to

The masses of two bodies are m_1 and m_2 the distance between them is d. What is the gravitational force between them?

Two thin rings each of radius R are placed at a distance 'd' apart. The charges on the rings are +q and -q. The potential difference between their centres will be -

Two conducting spheres of radii R each are given equal charges +Q and are kept such that their centre are at distance r (geR) . The force of attraction (F) between them is:

A total charge Q is broken in two parts Q_(1) and Q_(2) and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when

Force F between charges Q_(1) and Q_(2) separated by r is 25 N . It can be reduced to 5 N if the separation between them is made

Force F between charges Q_(1) and Q_(2) separated by r is 25 N. It can be reduced to 5 N, if separation between them is made of

Two concentric, thin metallic spheres of radii R_(1) and R_(2) (R_(1) gt R_(2)) charges Q_(1) and Q_(2) respectively Then the potential at radius r between R_(1) and R_(2) will be (k = 1//4pi in)